Which field is more rigorous, mathematics or philosophy? Adding labels on map layout legend boxes using QGIS. Try this: mydataset <- lapply(mydataset[[1]], as.factor), It's still not working :( This turn the whole dataset into a list, My bad, mydataset[[1]] <- lapply(mydataset[[1]], as.factor), Convert list variables in a dataset into factor, How terrifying is giving a conference talk? I have a nested list of data. I do a bit of sub setting first and then I start a for loop from i to R where R are is the amount of subsets i put in my list(). We use mutate_all for applying the function to each column, and within that use map as the columns itself are list of elements. I don't know how to get it out of the list of lists. Thanks for contributing an answer to Stack Overflow! What is the state of the art of splitting a binary file by size? Is there an identity between the commutative identity and the constant identity? The above will convert all character columns to factors, to avoid this you can add a parameter to the data.frame() call: You can use the plyr package. Is Gathered Swarm's DC affected by a Moon Sickle? What does "rooting for my alt" mean in Stranger Things? Thanks for posting this. What is the advantage of calling two functions instead of one? The contain of pair is always vector with two strings . vectorized expression to rbind a list of dataframes? Is iMac FusionDrive->dual SSD migration any different from HDD->SDD upgrade from Time Machine perspective? Historical installed base figures for early lines of personal computer. Are high yield savings accounts as secure as money market checking accounts? Note: If youre working with an extremely large list, the flatten_* functions will perform quicker than the unlist() function from base R. How to Convert List to a Data Frame in R The Overflow #186: Do large language models know what theyre talking about? Making statements based on opinion; back them up with references or personal experience. Viewed 35k times Part of R Language Collective 10 I have the following list of list. See R FAQ 7.21 you deserve a medal. For example, let's print each column using a for loop: To subscribe to this RSS feed, copy and paste this URL into your RSS reader. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. If I am writing a script and don't know in advance what the variable name (var.name) will be (which seems to be the point of the assign function), I can't simply put x <- 6 because var.name might have been "y". Historical installed base figures for early lines of personal computer? Not the answer you're looking for? How to convert a variable value to string in R? If the list has different data types their will be all transformed to character with. Thanks for any and all help and please, let me know if you need any clarification! Asking for help, clarification, or responding to other answers. Denys Fisher, of Spirograph fame, using a computer late 1976, early 1977. Other than assign, one other way to assign value to string named object is to access .GlobalEnv directly. Any chance you could re-write your question with actual questions? Why can you not divide both sides of the equation, when working with exponential functions? Required fields are marked *. To learn more, see our tips on writing great answers. Your email address will not be published. Find centralized, trusted content and collaborate around the technologies you use most. http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-turn-a-string-into-a-variable_003f, There is another simple solution found there: It turned all values in figures. > head(fact_dataset) var_1 var_2 var_3 var_4 var_5 var_6 1: 1 2 6 4 2 14 2: 1 2 6 4 2 14 3: 2 4 1 5 2 6 4: 2 1 5 5 2 10 5: 2 1 5 5 2 1 6: 2 3 1 4 4 8 And the str() now looks like this: > str(yoo) Classes data.table and 'data.frame': 83 obs. Part of R Language Collective 77 I have a list of named values: myList <- list ('A' = 1, 'B' = 2, 'C' = 3) I want a vector with the value 1:3 I can't figure out how to extract the values without defining a function. of 6 variables: $ var_1 :List of 83 ..$ : int 1 ..$ : int 1. Why does tblr not work with commands that contain &? Based on the question title, they just look for a way to convert list to data frame. From your previous edit, I'm guessing you are doing all of this to make bubble plots. 1 1 2 3 Update: Ran across this post on r-bloggers which has this example: In fiddling with this, I'm finding it interesting that the following are not equivalent: Update2: The above works to output values but not in trying to plot. Returns TRUE or FALSE Use as.foo to explicitly convert it. Use string within a variable to create new variable name, How to name an object out of a string in R, how to get value when a variable name is passed as a string, R: Convert variable name to string in sapply. Syntax: select (dataframe,column1,column2,.,column n) Here, data frame is the input dataframe and columns are the columns in the dataframe to be displayed Example 1: R program to select columns R library(dplyr) data1=data.frame(id=c(1,2,3,4,5,6,7,1,4,2), name=c('sravan','ojaswi','bobby','gnanesh', 'rohith','pinkey','dhanush', How to convert the list to String in R? The Overflow #186: Do large language models know what theyre talking about? doesn't work with the sample data provided in the question. How would you get a medieval economy to accept fiat currency? This method converts a list to a data frame faster than the previous method if youre working with a very large dataset. There is one difference with @Alex Brown's solution compared to yours, going your route yielded the following warning message for some reason: `Warning message: In data.row.names(row.names, rowsi, i) : some row.names duplicated: 3,4 --> row.names NOT used'. How to Convert List to Vector in R (With Examples) You can use one of the following methods to convert a list to a vector in R: #use unlist () function new_vector <- unlist (my_list, use.names = FALSE) #use flatten_* () function from purrr library new_vector <- purrr::flatten (my_list) Find centralized, trusted content and collaborate around the technologies you use most. Buyer beware is a rather blas way of saying that you should almost never do this, because its almost never a good solution to a given problem. What would a potion that increases resistance to damage actually do to the body? It doesn't work on my dataset. Connect and share knowledge within a single location that is structured and easy to search. Find out all the different files from two different paths efficiently in Windows (with Python), Excel Needs Key For Microsoft 365 Family Subscription, Pros and cons of "anything-can-happen" UB versus allowing particular deviations from sequential progran execution. How should a time traveler be careful if they decide to stay and make a family in the past? Oddly, though, I can do this: Why different behavior when stored as a variable vs. executed within the symbol function? R Language Collective See more This question is in a collective: a subcommunity defined by tags with relevant content and experts. Here goes with some example data. So, what exactly are strings? When a customer buys a product with a credit card, does the seller receive the money in installments or completely in one transaction? Thank you very much, this is the simplest solution. dataframe? Conclusions from title-drafting and question-content assistance experiments Read text file in R and convert it to a character object. The tibble package has a function enframe() that solves this problem by coercing nested list objects to nested tibble ("tidy" data frame) objects. What would a potion that increases resistance to damage actually do to the body? Denys Fisher, of Spirograph fame, using a computer late 1976, early 1977. assign is good, but I have not found a function for referring back to the variable you've created in an automated script. By clicking Post Your Answer, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct. e.g. Zerk caps for trailer bearings Installation, tools, and supplies, Future society where tipping is mandatory, The shorter the message, the larger the prize. Rivers of London short about Magical Signature, Sidereal time of rising and setting of the sun on the arctic circle. Converting multiple data.table columns to factors in R, Convert factor variable of strings to list of integers using data.table, Converting a List of Variables into a data.table object, Converting list of data frames to a data table, Assign/Extract values from list in data.table to columns, Turning a column of a data.table into a list in the same data.table, Assigning attributes to factors with a list. Not the answer you're looking for? Not the answer you're looking for? What would a potion that increases resistance to damage actually do to the body? Is Gathered Swarm's DC affected by a Moon Sickle? the sample provided here isn't the one provided by the question. Asking for help, clarification, or responding to other answers. What's it called when multiple concepts are combined into a single problem? When a customer buys a product with a credit card, does the seller receive the money in installments or completely in one transaction? You can use then use x to refer to the variable with name string. Method 1: Base R The following code snippet shows how to convert a list to a data frame using only base R: #create list my_list <- list (letters [1:5], letters [6:10]) my_list [ [1]] [1] "a" "b" "c" "d" "e" [ [2]] [1] "f" "g" "h" "i" "j" #convert list to data frame data.frame (t (sapply (my_list,c))) X1 X2 X3 X4 X5 1 a b c d e 2 f g h i j Multiplication implemented in c++ with constant time. Thanks for contributing an answer to Stack Overflow! I can't do: I get invalid symbol coordinates. Fixing the sample data so it matches the original description 'each item is a list of length 20'. To learn more, see our tips on writing great answers. So maybe you need a spread step or something. Why is the Work on a Spring Independent of Applied Force? The loop is unefficient. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide, The future of collective knowledge sharing, Converting a list into a character object in R, How terrifying is giving a conference talk? If youd like to convert this data table to a data frame, you can simply use, bind_rows(my_list) Why can you not divide both sides of the equation, when working with exponential functions? Then I call RNumberList[[i]], transfer it to LoopVariable and do a few calculations which (works all fine) and then I want to convert the used subset Variable name in my list() to a string so that this string can be used as an unique identifier in my export filename! (Ep. Why does this journey to the moon take so long? Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. I know I can do what you did, but it doesn't work to do. The Overflow Blog is there a way to convert a string with numbers to a list of numeric values? Are Tucker's Kobolds scarier under 5e rules than in previous editions? US Port of Entry would be LAX and destination is Boston. What is the motivation for infinity category theory? This method suffers from the null situation. There are many cases in which you might want to convert a list to a data frame in R. This tutorial explains three different ways to do so. Future society where tipping is mandatory. Why was there a second saw blade in the first grail challenge? I have tried so many ways to work around this issue and you're telling me there is a function called "get". The result is the same as using the parameter use.names=FALSE. By clicking Post Your Answer, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct. How do you create a string from variables? If the values are of type factor, then you should convert them by as.numeric(as.character(unlist(tmpseqsf[[1]]))). By clicking Post Your Answer, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct. Creating strings is as simple as assigning a value to a variable. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. rev2023.7.14.43533. Making statements based on opinion; back them up with references or personal experience. (Ep. How would you get a medieval economy to accept fiat currency? I checked the class of set[[1]] and it's a factor. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Are glass cockpit or steam gauge GA aircraft safer? Asking for help, clarification, or responding to other answers. And if you have values in double quotes it considers as a String, use paste () or toString () methods to merge all elements from the list into a string value with or without a delimiter. the result of this answer on the original dataset is incorrect. Works - greatly appreciate your help here!. In Indiana Jones and the Last Crusade (1989), when does this shot of Sean Connery happen? Where to start with a large crack the lock puzzle like this? Tx, plyr is being deprecated in favour of dplyr. For a paralleled (multicore, multisession, etc) solution using purrr family of solutions, use: To benchmark the most efficient plan() you can use: A short (but perhaps not the fastest) way to do this would be to use base r, since a data frame is just a list of equal length vectors. Find centralized, trusted content and collaborate around the technologies you use most. I would like to convert a list as follows: I referred to this stack overflow post but couldn't solve it. Nice one! Should I include high school teaching activities in an academic CV? 589). My goal is to convert these variables to factor variables. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. This is the most concise answer I found. Starting the Prompt Design Site: A New Home in our Stack Exchange Neighborhood, Temporary policy: Generative AI (e.g., ChatGPT) is banned. Making statements based on opinion; back them up with references or personal experience. Try out these two lines to see how it works: If you want to use a string as a variable name, you can use assign: Subsetting the data and combining them back is unnecessary. Keep in mind the useful as.name() tool as well, for converting strings to variable names. My goal is to convert these variables to factor variables. # A tibble: 2 x 3 Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. This can be done by using unlist before as.vector. Syntax as.numeric (unlist (data)) Parameters I am using R to parse a list of strings in the form: original_string <- "variable_name=variable_value" First, I extract the variable name and value from the original string and convert the value to numeric class. It contains two variables: pair and genes. It might be nice to note in the answer that it does something similar--but distinctly different than--pretty much all the other answers. There is one in the title but no concise statement of what exactly you are trying to do. And the names of the columns in the resulting Data Frame are set! Are Tucker's Kobolds scarier under 5e rules than in previous editions? In Indiana Jones and the Last Crusade (1989), when does this shot of Sean Connery happen? Explaining Ohm's Law and Conductivity's constance at particle level. Multiplication implemented in c++ with constant time. I have a more complicated data set with 3+ colors and complicated subsets, but I do something like this: I know you can have a variable evaluated to specify the column (like var="cu"; set1[,var]; I want to know how to get a variable to specify the data.frame itself (and another to evaluate the column). I needed to convert a list to a data.frame when the length of the objects in the list were of unequal length. Imho the BEST answer. If you would rather just work with an example row of df, here is the output: I have unsuccessfully tried using rbind.data.frame, do.call(rbind), sapply, and other methods that I found here on SO. This method seems to return the correct object, but on inspecting the object, you'll find that the columns are lists rather than vectors, which can lead to problems down the line if you are not expecting it.